The mass of a metal bar has a mass of 13.2 g. Using the water-displacement method a student finds the initial volume level on a graduated cylinder is 11.0 ml. The final volume was 13.4 ml. What is the metal’s density?
(13.2 g) / (13.4 ml - 11.0 ml) = 5.50 g/ml
Look dude, I'm not gonna do your chemistry homework for you, but I'll tell you the process and you can do the math yourself, that way you learn the process and don't get screwed on the test :)
1. Subtract the initial volume of the cylinder from the final volume of the cylinder to get the volume of the metal bar
2. Divide the metal bar's mass by the metal bar's volume
That's it. Your answer should look something like "The metal bar's density is x grams per cubic centimeter"
Edit: never mind everyone else just gave you the answer.
The bar displaces 2.4 ml. 1 ml is equal to 1 cubic centimeter
13.2 grams / 2.4 cm^3 =>
(132/24) grams/cm^3 =>
(12 * 11 / (12 * 2)) grams/cm^3 =>
D = m/V = 13.2g / [13.4 - 11.0]mL <<< use a calculator