Ade throws a ball up to a height of 10m and catches it back. What is the displacement of the ball?
The ball was initially in the hand and finally in the hand.
since displacement is the distance moved from its initial position, the displacement is zero.
Displacement = final height -initial height = 0-0 = 0
motion = 10 m+10 m = 20 m
Since you did not select 0m as best answer i'm going with (B) 20m as being the correct answer.
(B) Absolute value of displacement = 2(10m) = 20m = 2[.5(V1 + u)t1]
(D) Net value of displacement = (10 - 10)m = 0m = [.5(v1 + 0)t1] - [.5(0 + v2)t2]
But the maximum net displacement at at any given time during the ball's flight = (A) 10M
10 m up and 10 m down. 20 m.
Displacement is time dependent
The maximum displacement is 10 m halfway through the ball's flight.
When Ade catches it again, total displacement is zero.
D. 0m is probably the answer sought.
I hope this helps.
Please remember to vote a "Best Answer" from among your results. It s good karma as it helps keep the exchange in balance.
0. It ended up where it started so it hasn’t moved at all.