If we assume the width of the rectangle as x, then the length is 2x as the 'rectangle is twice as long as it is wide'.

Twice the length added to twice the width is the perimeter of any rectangle.

With x as width and 2x as length, the perimeter is 2(x+2x)., which is given as 162 feet.

2(x + 2x) = 2x +4x.i.e., 6x.

6x = 162.

x = 27 feet.

x(width) = 27 ft.

2x(length) =54 ft.

2 ( l = 2w ) + 2 w = 162ft , 4w+2w = 162ft , 6w = 162ft , so w = 162/6 =27ft ; since l = 2w , therefore l =2x27 ft = 54ft

2L + 2B = 162

4B + 2B = 162

6B = 162

B = 27 ft

L = 54 ft

The length of the rectangle is 54 feet and its width is 27 feet.

Let the width be x

Therefore the length will be 2x

Now we know perimeter that is 162ft.

Therefore,according to condition, 2(2x+x)=162

Therefore after solving we get x=27 and 2x=54

Therefore width=x=27 and length=2x=54

Hope this helps

27 X 54

If a short side of the rectangle is A, then a long side is 2A. There are two long and two short sides, so you have a total of 6A = 162 ft. 162 divided by 6 is 27. Got it?

2L = W

P = 162 = 2L + 2W

162 = W + 2W

3W = 162

W = 54 ft

Dimensions are 54ft by 27ft.

If the width of rectangle is W

then length, L = 2W

Perimeter = 2L + 2W

162 = 2(2W)+2W

162 = 6W

W = 27 feet

L = 2(27) = 54 feet

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